Parse date(today) into a fixed - user local independent - format?

B

Dear All,

1) How can you ensure that the output of function today() is independent from the user local? I get different formats of the same date depending the date format settings of the user.

 

2) I am looking to use this format: DDMMYY; thus for instance 240919.

 

Thanks,

Bas

 

Ninox Profile

Try 

format(today(), "DDMMYY")

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